var A: array[-3..2] of integer;
X = [1 3 5 7 9 11]
for k:=1 to 6 do begin ... end;
X = [12 9 6 3 0 -3]
X = [3 4 7 8 11 12]
X = [1 2 4 8 16 32]
X[1] := 1; for k:=2 to 6 do begin ... end;
for k:=1 to N do writeln ( ... );
k := 2; while k <= N do begin writeln ( A[k] ); ... end;
S := 0; for k := 1 to N do begin ... end;
S := 0; for k := 1 to N do begin if . . . then S := S + X[k]; end;
S := 0; for j:=1 to N do if ... then S := S + 1;